Base | Representation |
---|---|
bin | 1100000111011001011100… |
… | …1100111011100111100001 |
3 | 1202011111102110001021211022 |
4 | 3001312113030323213201 |
5 | 3221223334431200213 |
6 | 44155404433255225 |
7 | 2543266335366560 |
oct | 301662714734741 |
9 | 52144373037738 |
10 | 13321230334433 |
11 | 427655827052a |
12 | 15b18b1104515 |
13 | 758257047398 |
14 | 340a729d7bd7 |
15 | 1817b0ae0308 |
hex | c1d9733b9e1 |
13321230334433 has 32 divisors (see below), whose sum is σ = 15619255491840. Its totient is φ = 11126139678720.
The previous prime is 13321230334393. The next prime is 13321230334457. The reversal of 13321230334433 is 33443303212331.
It is a cyclic number.
It is not a de Polignac number, because 13321230334433 - 214 = 13321230318049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13321230334393 and 13321230334402.
It is not an unprimeable number, because it can be changed into a prime (13321230364433) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 28067423 + ... + 28538091.
It is an arithmetic number, because the mean of its divisors is an integer number (488101734120).
Almost surely, 213321230334433 is an apocalyptic number.
It is an amenable number.
13321230334433 is a deficient number, since it is larger than the sum of its proper divisors (2298025157407).
13321230334433 is an equidigital number, since it uses as much as digits as its factorization.
13321230334433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 471417.
The product of its (nonzero) digits is 139968, while the sum is 35.
Adding to 13321230334433 its reverse (33443303212331), we get a palindrome (46764533546764).
The spelling of 13321230334433 in words is "thirteen trillion, three hundred twenty-one billion, two hundred thirty million, three hundred thirty-four thousand, four hundred thirty-three".
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