Base | Representation |
---|---|
bin | 1100000111111110111101… |
… | …1010111101001001100011 |
3 | 1202012110102020112120222102 |
4 | 3001333233122331021203 |
5 | 3221410000341342243 |
6 | 44204152000401015 |
7 | 2544104023131410 |
oct | 301775732751143 |
9 | 52173366476872 |
10 | 13331300340323 |
11 | 427a85554aa49 |
12 | 15b384161616b |
13 | 7591a03a5c54 |
14 | 34134a181107 |
15 | 181b9ebca9b8 |
hex | c1fef6bd263 |
13331300340323 has 16 divisors (see below), whose sum is σ = 15285154719744. Its totient is φ = 11389793580960.
The previous prime is 13331300340313. The next prime is 13331300340419. The reversal of 13331300340323 is 32304300313331.
It is a cyclic number.
It is not a de Polignac number, because 13331300340323 - 242 = 8933253829219 is a prime.
It is a super-2 number, since 2×133313003403232 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13331300340313) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 151642886 + ... + 151730772.
It is an arithmetic number, because the mean of its divisors is an integer number (955322169984).
Almost surely, 213331300340323 is an apocalyptic number.
13331300340323 is a deficient number, since it is larger than the sum of its proper divisors (1953854379421).
13331300340323 is an equidigital number, since it uses as much as digits as its factorization.
13331300340323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 157882.
The product of its (nonzero) digits is 17496, while the sum is 29.
Adding to 13331300340323 its reverse (32304300313331), we get a palindrome (45635600653654).
The spelling of 13331300340323 in words is "thirteen trillion, three hundred thirty-one billion, three hundred million, three hundred forty thousand, three hundred twenty-three".
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