Base | Representation |
---|---|
bin | 1100000111111111000000… |
… | …0011101100110001000010 |
3 | 1202012110102222122020021120 |
4 | 3001333300003230301002 |
5 | 3221410011110133442 |
6 | 44204153021333110 |
7 | 2544104212664643 |
oct | 301776003546102 |
9 | 52173388566246 |
10 | 13331311021122 |
11 | 427a860585656 |
12 | 15b3845107196 |
13 | 7591a2675653 |
14 | 34134b7616ca |
15 | 181ba0ada4ec |
hex | c1ff00ecc42 |
13331311021122 has 16 divisors (see below), whose sum is σ = 26662881248832. Its totient is φ = 4443727139280.
The previous prime is 13331311021051. The next prime is 13331311021123. The reversal of 13331311021122 is 22112011313331.
It is a junction number, because it is equal to n+sod(n) for n = 13331311021092 and 13331311021101.
It is not an unprimeable number, because it can be changed into a prime (13331311021123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10128454 + ... + 11368737.
It is an arithmetic number, because the mean of its divisors is an integer number (1666430078052).
Almost surely, 213331311021122 is an apocalyptic number.
13331311021122 is an abundant number, since it is smaller than the sum of its proper divisors (13331570227710).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13331311021122 is a wasteful number, since it uses less digits than its factorization.
13331311021122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21600553.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 13331311021122 its reverse (22112011313331), we get a palindrome (35443322334453).
The spelling of 13331311021122 in words is "thirteen trillion, three hundred thirty-one billion, three hundred eleven million, twenty-one thousand, one hundred twenty-two".
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