Base | Representation |
---|---|
bin | 11110010101011000111111… |
… | …101101110010000001011011 |
3 | 122111100222222212220211211100 |
4 | 132111120333231302001123 |
5 | 114441302412314124311 |
6 | 1151424154104002443 |
7 | 40046436310561002 |
oct | 3625307755620133 |
9 | 574328885824740 |
10 | 133411343114331 |
11 | 39566484185a57 |
12 | 12b68018a60423 |
13 | 5959835762a99 |
14 | 24d3201921c39 |
15 | 106550644da56 |
hex | 79563fb7205b |
133411343114331 has 48 divisors (see below), whose sum is σ = 198059161626144. Its totient is φ = 86473432092672.
The previous prime is 133411343114251. The next prime is 133411343114341.
133411343114331 is a `hidden beast` number, since 1 + 3 + 3 + 4 + 1 + 1 + 3 + 4 + 311 + 4 + 331 = 666.
133411343114331 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 133411343114331 - 211 = 133411343112283 is a prime.
It is a super-2 number, since 2×1334113431143312 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (133411343114341) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2641940475 + ... + 2641990971.
It is an arithmetic number, because the mean of its divisors is an integer number (4126232533878).
Almost surely, 2133411343114331 is an apocalyptic number.
133411343114331 is a deficient number, since it is larger than the sum of its proper divisors (64647818511813).
133411343114331 is a wasteful number, since it uses less digits than its factorization.
133411343114331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56220 (or 56217 counting only the distinct ones).
The product of its digits is 46656, while the sum is 36.
The spelling of 133411343114331 in words is "one hundred thirty-three trillion, four hundred eleven billion, three hundred forty-three million, one hundred fourteen thousand, three hundred thirty-one".
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