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1334134502153 = 43271997114833
BaseRepresentation
bin10011011010100000100…
…111001111001100001001
311201112122010102211022122
4103122200213033030021
5133324301413032103
62500520512301025
7165250045105355
oct23324047171411
94645563384278
101334134502153
11474892166952
12196692b41775
1398a67c149cb
1448802b5a465
1524a859e1b38
hex136a09cf309

1334134502153 has 16 divisors (see below), whose sum is σ = 1371584645376. Its totient is φ = 1296986100480.

The previous prime is 1334134502069. The next prime is 1334134502177. The reversal of 1334134502153 is 3512054314331.

It is a cyclic number.

It is not a de Polignac number, because 1334134502153 - 212 = 1334134498057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1334134502453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11560625 + ... + 11675457.

It is an arithmetic number, because the mean of its divisors is an integer number (85724040336).

Almost surely, 21334134502153 is an apocalyptic number.

It is an amenable number.

1334134502153 is a deficient number, since it is larger than the sum of its proper divisors (37450143223).

1334134502153 is a wasteful number, since it uses less digits than its factorization.

1334134502153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 116144.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 1334134502153 its reverse (3512054314331), we get a palindrome (4846188816484).

The spelling of 1334134502153 in words is "one trillion, three hundred thirty-four billion, one hundred thirty-four million, five hundred two thousand, one hundred fifty-three".

Divisors: 1 43 271 997 11653 42871 114833 270187 4937819 11618041 31119743 114488501 1338148949 4923005543 31026383771 1334134502153