Base | Representation |
---|---|
bin | 1100001000100111100110… |
… | …1111111001100011110001 |
3 | 1202020111120121220121012021 |
4 | 3002021321233321203301 |
5 | 3222044322010133131 |
6 | 44213154354231441 |
7 | 2544641266315240 |
oct | 302117157714361 |
9 | 52214517817167 |
10 | 13342211021041 |
11 | 4284444321951 |
12 | 15b5987585581 |
13 | 75a21b959446 |
14 | 341aa3240957 |
15 | 1820dc9c4e11 |
hex | c2279bf98f1 |
13342211021041 has 16 divisors (see below), whose sum is σ = 15634059170688. Its totient is φ = 11147314147200.
The previous prime is 13342211021023. The next prime is 13342211021047. The reversal of 13342211021041 is 14012011224331.
It is not a de Polignac number, because 13342211021041 - 231 = 13340063537393 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13342211020997 and 13342211021015.
It is not an unprimeable number, because it can be changed into a prime (13342211021047) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20376070 + ... + 21020671.
It is an arithmetic number, because the mean of its divisors is an integer number (977128698168).
Almost surely, 213342211021041 is an apocalyptic number.
It is an amenable number.
13342211021041 is a deficient number, since it is larger than the sum of its proper divisors (2291848149647).
13342211021041 is a wasteful number, since it uses less digits than its factorization.
13342211021041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41397912.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13342211021041 its reverse (14012011224331), we get a palindrome (27354222245372).
The spelling of 13342211021041 in words is "thirteen trillion, three hundred forty-two billion, two hundred eleven million, twenty-one thousand, forty-one".
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