Base | Representation |
---|---|
bin | 1100001001001111111101… |
… | …0110011101100001101001 |
3 | 1202021112112111010101200212 |
4 | 3002103333112131201221 |
5 | 3222234012330343103 |
6 | 44222145241110505 |
7 | 2545503560646152 |
oct | 302237726354151 |
9 | 52245474111625 |
10 | 13353042434153 |
11 | 4288aa2382934 |
12 | 15b7aaaa88435 |
13 | 75b256977a26 |
14 | 34240d988929 |
15 | 1825238627d8 |
hex | c24ff59d869 |
13353042434153 has 16 divisors (see below), whose sum is σ = 13455448129536. Its totient is φ = 13250896356240.
The previous prime is 13353042434131. The next prime is 13353042434177. The reversal of 13353042434153 is 35143424035331.
It is a cyclic number.
It is not a de Polignac number, because 13353042434153 - 28 = 13353042433897 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13353042434153.
It is not an unprimeable number, because it can be changed into a prime (13353042437153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 524396900 + ... + 524422362.
It is an arithmetic number, because the mean of its divisors is an integer number (840965508096).
Almost surely, 213353042434153 is an apocalyptic number.
It is an amenable number.
13353042434153 is a deficient number, since it is larger than the sum of its proper divisors (102405695383).
13353042434153 is a wasteful number, since it uses less digits than its factorization.
13353042434153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30404.
The product of its (nonzero) digits is 777600, while the sum is 41.
Adding to 13353042434153 its reverse (35143424035331), we get a palindrome (48496466469484).
The spelling of 13353042434153 in words is "thirteen trillion, three hundred fifty-three billion, forty-two million, four hundred thirty-four thousand, one hundred fifty-three".
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