Base | Representation |
---|---|
bin | 11110010111001000110000… |
… | …110101011011000101110011 |
3 | 122111210110202112211111212002 |
4 | 132113020300311123011303 |
5 | 120000234202222343403 |
6 | 1151555242334324215 |
7 | 40061215253105000 |
oct | 3627106065330563 |
9 | 574713675744762 |
10 | 133531352543603 |
11 | 396023683a0463 |
12 | 12b8732b95966b |
13 | 5967c4c89bcb1 |
14 | 24d8d482008a7 |
15 | 10686cc168188 |
hex | 797230d5b173 |
133531352543603 has 16 divisors (see below), whose sum is σ = 155998286860800. Its totient is φ = 114252149232648.
The previous prime is 133531352543599. The next prime is 133531352543689. The reversal of 133531352543603 is 306345253135331.
It is not a de Polignac number, because 133531352543603 - 22 = 133531352543599 is a prime.
It is a super-3 number, since 3×1335313525436033 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133531352543503) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 345547775 + ... + 345933992.
It is an arithmetic number, because the mean of its divisors is an integer number (9749892928800).
Almost surely, 2133531352543603 is an apocalyptic number.
133531352543603 is a deficient number, since it is larger than the sum of its proper divisors (22466934317197).
133531352543603 is an frugal number, since it uses more digits than its factorization.
133531352543603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 691482351 (or 691482337 counting only the distinct ones).
The product of its (nonzero) digits is 4374000, while the sum is 47.
The spelling of 133531352543603 in words is "one hundred thirty-three trillion, five hundred thirty-one billion, three hundred fifty-two million, five hundred forty-three thousand, six hundred three".
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