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133807004147 = 419754776143
BaseRepresentation
bin111110010011110000…
…1001101100111110011
3110210101020111002112102
41330213201031213303
54143014043113042
6141245312251015
712444601524545
oct1744741154763
9423336432472
10133807004147
1151824624753
1221b23840a6b
13c805821ccb
146694d41695
1537321b4b32
hex1f2784d9f3

133807004147 has 16 divisors (see below), whose sum is σ = 138531520512. Its totient is φ = 129152993280.

The previous prime is 133807004141. The next prime is 133807004153. The reversal of 133807004147 is 741400708331.

It is an interprime number because it is at equal distance from previous prime (133807004141) and next prime (133807004153).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133807004147 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 133807004147.

It is not an unprimeable number, because it can be changed into a prime (133807004141) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21778958 + ... + 21785100.

It is an arithmetic number, because the mean of its divisors is an integer number (8658220032).

Almost surely, 2133807004147 is an apocalyptic number.

133807004147 is a deficient number, since it is larger than the sum of its proper divisors (4724516365).

133807004147 is an equidigital number, since it uses as much as digits as its factorization.

133807004147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11758.

The product of its (nonzero) digits is 56448, while the sum is 38.

The spelling of 133807004147 in words is "one hundred thirty-three billion, eight hundred seven million, four thousand, one hundred forty-seven".

Divisors: 1 41 97 3977 5477 6143 224557 251863 531269 595871 21782029 24430711 33645211 1379453651 3263585467 133807004147