13381631041 has 3 divisors (see below), whose sum is σ = 13381746721. Its totient is φ = 13381515362.

The previous prime is 13381631033. The next prime is 13381631077. The reversal of 13381631041 is 14013618331.

The square root of 13381631041 is 115679.

It is a perfect power (a square), and thus also a powerful number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is not a de Polignac number, because 13381631041 - 2³ = 13381631033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13381630994 and 13381631012.

It is not an unprimeable number, because it can be changed into a prime (13381634041) by changing a digit.

It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 57840 + ... + 173518.

Almost surely, 2^13381631041 is an apocalyptic number.

13381631041 is the 115679-th square number.

13381631041 is the 57840-th centered octagonal number.

It is an amenable number.

13381631041 is a deficient number, since it is larger than the sum of its proper divisors (115680).

13381631041 is an frugal number, since it uses more digits than its factorization.

13381631041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 231358 (or 115679 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 31.

Multiplying 13381631041 by its product of nonzero digits (5184), we get a square (69370375316544 = 8328888²).

The spelling of 13381631041 in words is "thirteen billion, three hundred eighty-one million, six hundred thirty-one thousand, forty-one".