Base | Representation |
---|---|
bin | 11110011110001001101110… |
… | …111110011111001001000010 |
3 | 122120111120002110100001010010 |
4 | 132132021232332133021002 |
5 | 120031134001422202114 |
6 | 1153004530454245350 |
7 | 40141102522125552 |
oct | 3636115676371102 |
9 | 576446073301103 |
10 | 134013431444034 |
11 | 3977886036656a |
12 | 1304484b056856 |
13 | 59a1548c5322c |
14 | 25143db295162 |
15 | 1075ee47cac59 |
hex | 79e26ef9f242 |
134013431444034 has 16 divisors (see below), whose sum is σ = 268027646585472. Its totient is φ = 44671013198448.
The previous prime is 134013431444021. The next prime is 134013431444201. The reversal of 134013431444034 is 430444134310431.
It is a junction number, because it is equal to n+sod(n) for n = 134013431443983 and 134013431444001.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30419274 + ... + 34545029.
It is an arithmetic number, because the mean of its divisors is an integer number (16751727911592).
Almost surely, 2134013431444034 is an apocalyptic number.
134013431444034 is an abundant number, since it is smaller than the sum of its proper divisors (134014215141438).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134013431444034 is a wasteful number, since it uses less digits than its factorization.
134013431444034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65308121.
The product of its (nonzero) digits is 331776, while the sum is 39.
Adding to 134013431444034 its reverse (430444134310431), we get a palindrome (564457565754465).
The spelling of 134013431444034 in words is "one hundred thirty-four trillion, thirteen billion, four hundred thirty-one million, four hundred forty-four thousand, thirty-four".
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