Base | Representation |
---|---|
bin | 1100001100001010000100… |
… | …1111110011111100001011 |
3 | 1202110022111100012022022221 |
4 | 3003002201033303330023 |
5 | 3224043322312141303 |
6 | 44301131002354511 |
7 | 2552222625541633 |
oct | 303024117637413 |
9 | 52408440168287 |
10 | 13403003240203 |
11 | 42a81aaa05995 |
12 | 16057127bba37 |
13 | 762b89573a65 |
14 | 3449ccdd56c3 |
15 | 183999a644bd |
hex | c30a13f3f0b |
13403003240203 has 16 divisors (see below), whose sum is σ = 13446974509056. Its totient is φ = 13359102552640.
The previous prime is 13403003240191. The next prime is 13403003240261. The reversal of 13403003240203 is 30204230030431.
13403003240203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13403003240203 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13403003240503) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2714804751 + ... + 2714809687.
It is an arithmetic number, because the mean of its divisors is an integer number (840435906816).
Almost surely, 213403003240203 is an apocalyptic number.
13403003240203 is a deficient number, since it is larger than the sum of its proper divisors (43971268853).
13403003240203 is a wasteful number, since it uses less digits than its factorization.
13403003240203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10394.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 13403003240203 its reverse (30204230030431), we get a palindrome (43607233270634).
The spelling of 13403003240203 in words is "thirteen trillion, four hundred three billion, three million, two hundred forty thousand, two hundred three".
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