Base | Representation |
---|---|
bin | 1100001100010101101111… |
… | …1100011101010101000010 |
3 | 1202110121120122002220120020 |
4 | 3003011123330131111002 |
5 | 3224121231142144432 |
6 | 44302405453554310 |
7 | 2552363351423613 |
oct | 303053374352502 |
9 | 52417518086506 |
10 | 13406135506242 |
11 | 42a9567aa5806 |
12 | 16062477a5996 |
13 | 76326848830b |
14 | 344c08dcbc0a |
15 | 183acea3322c |
hex | c315bf1d542 |
13406135506242 has 64 divisors (see below), whose sum is σ = 27893700172800. Its totient is φ = 4290280816640.
The previous prime is 13406135506223. The next prime is 13406135506243. The reversal of 13406135506242 is 24260553160431.
13406135506242 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13406135506194 and 13406135506203.
It is not an unprimeable number, because it can be changed into a prime (13406135506243) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 23134018 + ... + 23706434.
It is an arithmetic number, because the mean of its divisors is an integer number (435839065200).
Almost surely, 213406135506242 is an apocalyptic number.
13406135506242 is an abundant number, since it is smaller than the sum of its proper divisors (14487564666558).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13406135506242 is a wasteful number, since it uses less digits than its factorization.
13406135506242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 573211.
The product of its (nonzero) digits is 518400, while the sum is 42.
Adding to 13406135506242 its reverse (24260553160431), we get a palindrome (37666688666673).
The spelling of 13406135506242 in words is "thirteen trillion, four hundred six billion, one hundred thirty-five million, five hundred six thousand, two hundred forty-two".
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