Base | Representation |
---|---|
bin | 11110100000000010101100… |
… | …100010100100010000100010 |
3 | 122120221222100011000112102210 |
4 | 132200002230202210100202 |
5 | 120040301001203044414 |
6 | 1153144330514022550 |
7 | 40153351233011664 |
oct | 3640025442442042 |
9 | 576858304015383 |
10 | 134143313331234 |
11 | 398189502a2809 |
12 | 13065a58277a56 |
13 | 59b0877511b1c |
14 | 251a7dcbb6534 |
15 | 10795970ace59 |
hex | 7a00ac8a4422 |
134143313331234 has 64 divisors (see below), whose sum is σ = 271910948567040. Its totient is φ = 44111351494080.
The previous prime is 134143313331211. The next prime is 134143313331281. The reversal of 134143313331234 is 432133313341431.
It is a super-2 number, since 2×1341433133312342 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134143313331192 and 134143313331201.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2862189069 + ... + 2862235935.
It is an arithmetic number, because the mean of its divisors is an integer number (4248608571360).
Almost surely, 2134143313331234 is an apocalyptic number.
134143313331234 is an abundant number, since it is smaller than the sum of its proper divisors (137767635235806).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134143313331234 is a wasteful number, since it uses less digits than its factorization.
134143313331234 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51895.
The product of its digits is 279936, while the sum is 39.
Adding to 134143313331234 its reverse (432133313341431), we get a palindrome (566276626672665).
The spelling of 134143313331234 in words is "one hundred thirty-four trillion, one hundred forty-three billion, three hundred thirteen million, three hundred thirty-one thousand, two hundred thirty-four".
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