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13513482057497 = 1914915797302171
BaseRepresentation
bin1100010010100101101001…
…0011000011011100011001
31202211212122210120201112212
43010221122103003130121
53232401102401314442
644424001415044505
72563213453153112
oct304513223033431
952755583521485
1013513482057497
114340043364574
121623005970735
1377041501a1b6
1434a0ada19209
151867b3bdda82
hexc4a5a4c3719

13513482057497 has 16 divisors (see below), whose sum is σ = 14321139768000. Its totient is φ = 12715477980480.

The previous prime is 13513482057443. The next prime is 13513482057533. The reversal of 13513482057497 is 79475028431531.

It is a cyclic number.

It is not a de Polignac number, because 13513482057497 - 214 = 13513482041113 is a prime.

It is a super-2 number, since 2×135134820574972 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13513482047497) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44570222 + ... + 44872392.

It is an arithmetic number, because the mean of its divisors is an integer number (895071235500).

Almost surely, 213513482057497 is an apocalyptic number.

It is an amenable number.

13513482057497 is a deficient number, since it is larger than the sum of its proper divisors (807657710503).

13513482057497 is a wasteful number, since it uses less digits than its factorization.

13513482057497 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 318136.

The product of its (nonzero) digits is 25401600, while the sum is 59.

The spelling of 13513482057497 in words is "thirteen trillion, five hundred thirteen billion, four hundred eighty-two million, fifty-seven thousand, four hundred ninety-seven".

Divisors: 1 19 149 2831 15797 300143 302171 2353753 5741249 44721307 45023479 855446101 4773395287 90694510453 711235897763 13513482057497