Base | Representation |
---|---|
bin | 1100010010100101101001… |
… | …0011000011011100011001 |
3 | 1202211212122210120201112212 |
4 | 3010221122103003130121 |
5 | 3232401102401314442 |
6 | 44424001415044505 |
7 | 2563213453153112 |
oct | 304513223033431 |
9 | 52755583521485 |
10 | 13513482057497 |
11 | 4340043364574 |
12 | 1623005970735 |
13 | 77041501a1b6 |
14 | 34a0ada19209 |
15 | 1867b3bdda82 |
hex | c4a5a4c3719 |
13513482057497 has 16 divisors (see below), whose sum is σ = 14321139768000. Its totient is φ = 12715477980480.
The previous prime is 13513482057443. The next prime is 13513482057533. The reversal of 13513482057497 is 79475028431531.
It is a cyclic number.
It is not a de Polignac number, because 13513482057497 - 214 = 13513482041113 is a prime.
It is a super-2 number, since 2×135134820574972 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13513482047497) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44570222 + ... + 44872392.
It is an arithmetic number, because the mean of its divisors is an integer number (895071235500).
Almost surely, 213513482057497 is an apocalyptic number.
It is an amenable number.
13513482057497 is a deficient number, since it is larger than the sum of its proper divisors (807657710503).
13513482057497 is a wasteful number, since it uses less digits than its factorization.
13513482057497 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 318136.
The product of its (nonzero) digits is 25401600, while the sum is 59.
The spelling of 13513482057497 in words is "thirteen trillion, five hundred thirteen billion, four hundred eighty-two million, fifty-seven thousand, four hundred ninety-seven".
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