Base | Representation |
---|---|
bin | 10011101011100011101… |
… | …110011010000000101001 |
3 | 11210021212220001221020110 |
4 | 103223203232122000221 |
5 | 134124244210333022 |
6 | 2513145201444533 |
7 | 166465506035640 |
oct | 23534356320051 |
9 | 4707786057213 |
10 | 1352440324137 |
11 | 481626339951 |
12 | 19a141640749 |
13 | 9a6c4601036 |
14 | 4965c034357 |
15 | 252a7b5900c |
hex | 13ae3b9a029 |
1352440324137 has 16 divisors (see below), whose sum is σ = 2061039157632. Its totient is φ = 772756400640.
The previous prime is 1352440324127. The next prime is 1352440324139. The reversal of 1352440324137 is 7314230442531.
It is not a de Polignac number, because 1352440324137 - 26 = 1352440324073 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1352440324095 and 1352440324104.
It is not an unprimeable number, because it can be changed into a prime (1352440324139) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2526888 + ... + 3014969.
It is an arithmetic number, because the mean of its divisors is an integer number (128814947352).
Almost surely, 21352440324137 is an apocalyptic number.
It is an amenable number.
1352440324137 is a deficient number, since it is larger than the sum of its proper divisors (708598833495).
1352440324137 is a wasteful number, since it uses less digits than its factorization.
1352440324137 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5553488.
The product of its (nonzero) digits is 241920, while the sum is 39.
Adding to 1352440324137 its reverse (7314230442531), we get a palindrome (8666670766668).
The spelling of 1352440324137 in words is "one trillion, three hundred fifty-two billion, four hundred forty million, three hundred twenty-four thousand, one hundred thirty-seven".
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