Base | Representation |
---|---|
bin | 11001001110000111… |
… | …11110000111001001 |
3 | 1021221122101011211120 |
4 | 30213003332013021 |
5 | 210212301113103 |
6 | 10115330345453 |
7 | 656353155426 |
oct | 144703760711 |
9 | 37848334746 |
10 | 13540254153 |
11 | 5819136398 |
12 | 275a72b289 |
13 | 137a2ac20a |
14 | 9263dcd4d |
15 | 543abc253 |
hex | 3270fe1c9 |
13540254153 has 16 divisors (see below), whose sum is σ = 18335364096. Its totient is φ = 8886965760.
The previous prime is 13540254151. The next prime is 13540254157. The reversal of 13540254153 is 35145204531.
It is not a de Polignac number, because 13540254153 - 21 = 13540254151 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13540254151) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 66226 + ... + 177387.
It is an arithmetic number, because the mean of its divisors is an integer number (1145960256).
Almost surely, 213540254153 is an apocalyptic number.
It is an amenable number.
13540254153 is a deficient number, since it is larger than the sum of its proper divisors (4795109943).
13540254153 is a wasteful number, since it uses less digits than its factorization.
13540254153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 243904.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 13540254153 its reverse (35145204531), we get a palindrome (48685458684).
The spelling of 13540254153 in words is "thirteen billion, five hundred forty million, two hundred fifty-four thousand, one hundred fifty-three".
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