Base | Representation |
---|---|
bin | 1100010111101000111001… |
… | …0100111110000110010010 |
3 | 1210011011122002220102122120 |
4 | 3011322032110332012102 |
5 | 3240311310101233132 |
6 | 44531512013515110 |
7 | 2602404660216234 |
oct | 305721624760622 |
9 | 53134562812576 |
10 | 13600254321042 |
11 | 4373921008474 |
12 | 16379a17a2a96 |
13 | 77866320c03c |
14 | 350381d8c254 |
15 | 188b919de02c |
hex | c5e8e53e192 |
13600254321042 has 16 divisors (see below), whose sum is σ = 27202780985952. Its totient is φ = 4533039383040.
The previous prime is 13600254321041. The next prime is 13600254321047. The reversal of 13600254321042 is 24012345200631.
13600254321042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13600254320994 and 13600254321012.
It is not an unprimeable number, because it can be changed into a prime (13600254321041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 94603183 + ... + 94746834.
It is an arithmetic number, because the mean of its divisors is an integer number (1700173811622).
Almost surely, 213600254321042 is an apocalyptic number.
13600254321042 is an abundant number, since it is smaller than the sum of its proper divisors (13602526664910).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13600254321042 is a wasteful number, since it uses less digits than its factorization.
13600254321042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 189361993.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 13600254321042 its reverse (24012345200631), we get a palindrome (37612599521673).
The spelling of 13600254321042 in words is "thirteen trillion, six hundred billion, two hundred fifty-four million, three hundred twenty-one thousand, forty-two".
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