Base | Representation |
---|---|
bin | 10011110011000101100… |
… | …100111000100110100001 |
3 | 11211001202021202212210111 |
4 | 103303011210320212201 |
5 | 134242323224233423 |
6 | 2521003304331321 |
7 | 200203030660450 |
oct | 23630544704641 |
9 | 4731667685714 |
10 | 1360524446113 |
11 | 484aa4643398 |
12 | 19b818a73b41 |
13 | 9b3b23b8771 |
14 | 49bc7958b97 |
15 | 255cc71e60d |
hex | 13cc59389a1 |
1360524446113 has 16 divisors (see below), whose sum is σ = 1556964420480. Its totient is φ = 1164605066496.
The previous prime is 1360524446089. The next prime is 1360524446131. The reversal of 1360524446113 is 3116444250631.
It is a cyclic number.
It is not a de Polignac number, because 1360524446113 - 29 = 1360524445601 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1360524440113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23038458 + ... + 23097436.
It is an arithmetic number, because the mean of its divisors is an integer number (97310276280).
Almost surely, 21360524446113 is an apocalyptic number.
It is an amenable number.
1360524446113 is a deficient number, since it is larger than the sum of its proper divisors (196439974367).
1360524446113 is an equidigital number, since it uses as much as digits as its factorization.
1360524446113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63336.
The product of its (nonzero) digits is 207360, while the sum is 40.
Adding to 1360524446113 its reverse (3116444250631), we get a palindrome (4476968696744).
The spelling of 1360524446113 in words is "one trillion, three hundred sixty billion, five hundred twenty-four million, four hundred forty-six thousand, one hundred thirteen".
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