1361250330041 has 16 divisors (see below), whose sum is σ = 1586368882560. Its totient is φ = 1143919946880.

The previous prime is 1361250330019. The next prime is 1361250330053. The reversal of 1361250330041 is 1400330521631.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1361250330041 is a prime.

It is a super-2 number, since 2×1361250330041² (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1361250329986 and 1361250330013.

It is not an unprimeable number, because it can be changed into a prime (1361250330941) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5060996 + ... + 5323173.

It is an arithmetic number, because the mean of its divisors is an integer number (99148055160).

Almost surely, 2^{1361250330041} is an apocalyptic number.

It is an amenable number.

1361250330041 is a deficient number, since it is larger than the sum of its proper divisors (225118552519).

1361250330041 is a wasteful number, since it uses less digits than its factorization.

1361250330041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10384544.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 1361250330041 its reverse (1400330521631), we get a palindrome (2761580851672).

The spelling of 1361250330041 in words is "one trillion, three hundred sixty-one billion, two hundred fifty million, three hundred thirty thousand, forty-one".