Base | Representation |
---|---|
bin | 1100101111001001000111… |
… | …0110100111110101010011 |
3 | 1211120202212122122112212210 |
4 | 3023302101312213311103 |
5 | 3313420233320301321 |
6 | 45441211202523203 |
7 | 2643521114240031 |
oct | 313622166476523 |
9 | 54522778575783 |
10 | 14004040400211 |
11 | 450a0977a3114 |
12 | 16a20b0966503 |
13 | 7a776304c3c4 |
14 | 365b28cdb551 |
15 | 1944259a3b76 |
hex | cbc91da7d53 |
14004040400211 has 16 divisors (see below), whose sum is σ = 18679394736288. Its totient is φ = 9332356857600.
The previous prime is 14004040400197. The next prime is 14004040400219. The reversal of 14004040400211 is 11200404040041.
It is not a de Polignac number, because 14004040400211 - 210 = 14004040399187 is a prime.
It is a super-2 number, since 2×140040404002112 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (14004040400219) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 230447071 + ... + 230507831.
It is an arithmetic number, because the mean of its divisors is an integer number (1167462171018).
Almost surely, 214004040400211 is an apocalyptic number.
14004040400211 is a deficient number, since it is larger than the sum of its proper divisors (4675354336077).
14004040400211 is a wasteful number, since it uses less digits than its factorization.
14004040400211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 89702.
The product of its (nonzero) digits is 512, while the sum is 21.
Adding to 14004040400211 its reverse (11200404040041), we get a palindrome (25204444440252).
The spelling of 14004040400211 in words is "fourteen trillion, four billion, forty million, four hundred thousand, two hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •