Base | Representation |
---|---|
bin | 11010000101100001… |
… | …10110100010010010 |
3 | 1100011000212221100221 |
4 | 31002300312202102 |
5 | 212140240120214 |
6 | 10233411503254 |
7 | 1004025400501 |
oct | 150260664222 |
9 | 40130787327 |
10 | 14005004434 |
11 | 5a37507133 |
12 | 286a2b7b2a |
13 | 1422671995 |
14 | 96c01a838 |
15 | 56e7c0e24 |
hex | 342c36892 |
14005004434 has 32 divisors (see below), whose sum is σ = 21691950336. Its totient is φ = 6777262080.
The previous prime is 14005004401. The next prime is 14005004471. The reversal of 14005004434 is 43440050041.
It is a super-2 number, since 2×140050044342 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14005004399 and 14005004408.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12146002 + ... + 12147154.
It is an arithmetic number, because the mean of its divisors is an integer number (677873448).
Almost surely, 214005004434 is an apocalyptic number.
14005004434 is a deficient number, since it is larger than the sum of its proper divisors (7686945902).
14005004434 is a wasteful number, since it uses less digits than its factorization.
14005004434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2250.
The product of its (nonzero) digits is 3840, while the sum is 25.
Adding to 14005004434 its reverse (43440050041), we get a palindrome (57445054475).
The spelling of 14005004434 in words is "fourteen billion, five million, four thousand, four hundred thirty-four".
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