Base | Representation |
---|---|
bin | 10100011010000111100… |
… | …001110000100001000011 |
3 | 11222001220222022200211222 |
4 | 110122013201300201003 |
5 | 140434140334042011 |
6 | 2552134024425255 |
7 | 203215412523302 |
oct | 24320741604103 |
9 | 4861828280758 |
10 | 1402433112131 |
11 | 4a084aa26467 |
12 | 1a797401822b |
13 | a2330a171ac |
14 | 4bc41808439 |
15 | 26731a76ddb |
hex | 14687870843 |
1402433112131 has 16 divisors (see below), whose sum is σ = 1411263786240. Its totient is φ = 1393636779360.
The previous prime is 1402433112107. The next prime is 1402433112133. The reversal of 1402433112131 is 1312113342041.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1402433112131 is a prime.
It is a super-2 number, since 2×14024331121312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1402433112131.
It is not an unprimeable number, because it can be changed into a prime (1402433112133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 147946850 + ... + 147956328.
It is an arithmetic number, because the mean of its divisors is an integer number (88203986640).
Almost surely, 21402433112131 is an apocalyptic number.
1402433112131 is a deficient number, since it is larger than the sum of its proper divisors (8830674109).
1402433112131 is an equidigital number, since it uses as much as digits as its factorization.
1402433112131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11194.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 1402433112131 its reverse (1312113342041), we get a palindrome (2714546454172).
The spelling of 1402433112131 in words is "one trillion, four hundred two billion, four hundred thirty-three million, one hundred twelve thousand, one hundred thirty-one".
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