Base | Representation |
---|---|
bin | 11010001000111111… |
… | …11110100101110011 |
3 | 1100020001200221120000 |
4 | 31010133332211303 |
5 | 212220214313121 |
6 | 10240332121043 |
7 | 1004531116452 |
oct | 150437764563 |
9 | 40201627500 |
10 | 14034135411 |
11 | 5a519a371a |
12 | 2878006183 |
13 | 142870124a |
14 | 971c40b99 |
15 | 572127526 |
hex | 3447fe973 |
14034135411 has 20 divisors (see below), whose sum is σ = 20969574912. Its totient is φ = 9353857968.
The previous prime is 14034135403. The next prime is 14034135421. The reversal of 14034135411 is 11453143041.
It is not a de Polignac number, because 14034135411 - 23 = 14034135403 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (14034135421) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 365070 + ... + 401676.
Almost surely, 214034135411 is an apocalyptic number.
14034135411 is a deficient number, since it is larger than the sum of its proper divisors (6935439501).
14034135411 is an equidigital number, since it uses as much as digits as its factorization.
14034135411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 41352 (or 41343 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 14034135411 its reverse (11453143041), we get a palindrome (25487278452).
The spelling of 14034135411 in words is "fourteen billion, thirty-four million, one hundred thirty-five thousand, four hundred eleven".
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