14040125511242 has 16 divisors (see below), whose sum is σ = 21465750026952. Its totient is φ = 6884976733440.

The previous prime is 14040125511241. The next prime is 14040125511259. The reversal of 14040125511242 is 24211552104041.

It can be written as a sum of positive squares in 4 ways, for example, as 13865636348281 + 174489162961 = 3723659^2 + 417719^2 .

It is a super-3 number, since 3×14040125511242³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14040125511199 and 14040125511208.

It is not an unprimeable number, because it can be changed into a prime (14040125511241) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25029059 + ... + 25583862.

Almost surely, 2^{14040125511242} is an apocalyptic number.

14040125511242 is a deficient number, since it is larger than the sum of its proper divisors (7425624515710).

14040125511242 is a wasteful number, since it uses less digits than its factorization.

14040125511242 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50615593.

The product of its (nonzero) digits is 12800, while the sum is 32.

Adding to 14040125511242 its reverse (24211552104041), we get a palindrome (38251677615283).

The spelling of 14040125511242 in words is "fourteen trillion, forty billion, one hundred twenty-five million, five hundred eleven thousand, two hundred forty-two".