14041124343153 has 20 divisors (see below), whose sum is σ = 20975123689828. Its totient is φ = 9360700122240.

The previous prime is 14041124343137. The next prime is 14041124343187. The reversal of 14041124343153 is 35134342114041.

14041124343153 is a `hidden beast` number, since 1 + 4 + 0 + 41 + 124 + 343 + 153 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 7168379728689 + 6872744614464 = 2677383^2 + 2621592^2 .

It is not a de Polignac number, because 14041124343153 - 2⁴ = 14041124343137 is a prime.

It is a super-3 number, since 3×14041124343153³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14041124343193) by changing a digit.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 21341925 + ... + 21989997.

Almost surely, 2^{14041124343153} is an apocalyptic number.

It is an amenable number.

14041124343153 is a deficient number, since it is larger than the sum of its proper divisors (6933999346675).

14041124343153 is an equidigital number, since it uses as much as digits as its factorization.

14041124343153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 915566 (or 915557 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 36.

Adding to 14041124343153 its reverse (35134342114041), we get a palindrome (49175466457194).

The spelling of 14041124343153 in words is "fourteen trillion, forty-one billion, one hundred twenty-four million, three hundred forty-three thousand, one hundred fifty-three".