Base | Representation |
---|---|
bin | 11010001011100000… |
… | …01001000111100011 |
3 | 1100021112020121020000 |
4 | 31011300021013203 |
5 | 212241104300201 |
6 | 10242402351043 |
7 | 1005204542565 |
oct | 150560110743 |
9 | 40245217200 |
10 | 14055150051 |
11 | 5a62847298 |
12 | 288305b483 |
13 | 142cb7b447 |
14 | 974951335 |
15 | 573dc8d86 |
hex | 345c091e3 |
14055150051 has 10 divisors (see below), whose sum is σ = 20995965012. Its totient is φ = 9370099980.
The previous prime is 14055150019. The next prime is 14055150089. The reversal of 14055150051 is 15005155041.
14055150051 is a `hidden beast` number, since 14 + 0 + 551 + 50 + 0 + 51 = 666.
It is not a de Polignac number, because 14055150051 - 25 = 14055150019 is a prime.
It is a super-2 number, since 2×140551500512 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 14055149997 and 14055150024.
It is not an unprimeable number, because it can be changed into a prime (14055150091) by changing a digit.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 86760105 + ... + 86760266.
Almost surely, 214055150051 is an apocalyptic number.
14055150051 is a deficient number, since it is larger than the sum of its proper divisors (6940814961).
14055150051 is an equidigital number, since it uses as much as digits as its factorization.
14055150051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 173520383 (or 173520374 counting only the distinct ones).
The product of its (nonzero) digits is 2500, while the sum is 27.
The spelling of 14055150051 in words is "fourteen billion, fifty-five million, one hundred fifty thousand, fifty-one".
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