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141014555403 = 3617547102103
BaseRepresentation
bin1000001101010100011…
…1110101101100001011
3111110222112202122010020
42003111013311230023
54302244211233103
6144440423151523
713121320641531
oct2032507655413
9443875678106
10141014555403
1154893049687
12233b55a55a3
13103b3b27337
146b7a288151
153a04d2a753
hex20d51f5b0b

141014555403 has 16 divisors (see below), whose sum is σ = 191128886016. Its totient is φ = 92455403040.

The previous prime is 141014555377. The next prime is 141014555413. The reversal of 141014555403 is 304555410141.

141014555403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 141014555403 - 25 = 141014555371 is a prime.

It is not an unprimeable number, because it can be changed into a prime (141014555413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1330050 + ... + 1432152.

It is an arithmetic number, because the mean of its divisors is an integer number (11945555376).

Almost surely, 2141014555403 is an apocalyptic number.

141014555403 is a deficient number, since it is larger than the sum of its proper divisors (50114330613).

141014555403 is a wasteful number, since it uses less digits than its factorization.

141014555403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 109714.

The product of its (nonzero) digits is 24000, while the sum is 33.

Adding to 141014555403 its reverse (304555410141), we get a palindrome (445569965544).

The spelling of 141014555403 in words is "one hundred forty-one billion, fourteen million, five hundred fifty-five thousand, four hundred three".

Divisors: 1 3 61 183 7547 22641 102103 306309 460367 1381101 6228283 18684849 770571341 2311714023 47004851801 141014555403