1411144000113 has 16 divisors (see below), whose sum is σ = 1898465026176. Its totient is φ = 932295356160.

The previous prime is 1411144000099. The next prime is 1411144000157. The reversal of 1411144000113 is 3110004411141.

It is not a de Polignac number, because 1411144000113 - 2²² = 1411139805809 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1411144000113.

It is not an unprimeable number, because it can be changed into a prime (1411144010113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1936348 + ... + 2563538.

It is an arithmetic number, because the mean of its divisors is an integer number (118654064136).

Almost surely, 2^{1411144000113} is an apocalyptic number.

It is an amenable number.

1411144000113 is a deficient number, since it is larger than the sum of its proper divisors (487321026063).

1411144000113 is a wasteful number, since it uses less digits than its factorization.

1411144000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 633944.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 1411144000113 its reverse (3110004411141), we get a palindrome (4521148411254).

The spelling of 1411144000113 in words is "one trillion, four hundred eleven billion, one hundred forty-four million, one hundred thirteen", and thus it is an aban number.