Base | Representation |
---|---|
bin | 10100100010010010001… |
… | …101111111000111001011 |
3 | 11222220120010022100011011 |
4 | 110202102031333013023 |
5 | 141110120304204003 |
6 | 3000144125144351 |
7 | 203645624410165 |
oct | 24422215770713 |
9 | 4886503270134 |
10 | 1411202413003 |
11 | 4a453aa76a59 |
12 | 1a96009bb0b7 |
13 | a30ca751c16 |
14 | 4c434329935 |
15 | 26a9688346d |
hex | 1489237f1cb |
1411202413003 has 16 divisors (see below), whose sum is σ = 1427011762176. Its totient is φ = 1395435373920.
The previous prime is 1411202413001. The next prime is 1411202413031. The reversal of 1411202413003 is 3003142021141.
It is a cyclic number.
It is not a de Polignac number, because 1411202413003 - 21 = 1411202413001 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1411202413001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 264614325 + ... + 264619657.
It is an arithmetic number, because the mean of its divisors is an integer number (89188235136).
Almost surely, 21411202413003 is an apocalyptic number.
1411202413003 is a deficient number, since it is larger than the sum of its proper divisors (15809349173).
1411202413003 is a wasteful number, since it uses less digits than its factorization.
1411202413003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8754.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 1411202413003 its reverse (3003142021141), we get a palindrome (4414344434144).
The spelling of 1411202413003 in words is "one trillion, four hundred eleven billion, two hundred two million, four hundred thirteen thousand, three".
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