Base | Representation |
---|---|
bin | 100000000101110001000110… |
… | …011010110010011100010001 |
3 | 200111201021000122201100221220 |
4 | 200011301012122302130101 |
5 | 121444314014013232113 |
6 | 1220055550433035253 |
7 | 41504403204614043 |
oct | 4005610632623421 |
9 | 614637018640856 |
10 | 141133806774033 |
11 | 40a73569633a07 |
12 | 139b48163b5b29 |
13 | 6099b2644a578 |
14 | 26bccac615a93 |
15 | 114b332dbe523 |
hex | 805c466b2711 |
141133806774033 has 32 divisors (see below), whose sum is σ = 197388715885056. Its totient is φ = 89592832723968.
The previous prime is 141133806774007. The next prime is 141133806774047. The reversal of 141133806774033 is 330477608331141.
It is not a de Polignac number, because 141133806774033 - 210 = 141133806773009 is a prime.
It is not an unprimeable number, because it can be changed into a prime (141133806774053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 83011285 + ... + 84694397.
It is an arithmetic number, because the mean of its divisors is an integer number (6168397371408).
Almost surely, 2141133806774033 is an apocalyptic number.
It is an amenable number.
141133806774033 is a deficient number, since it is larger than the sum of its proper divisors (56254909111023).
141133806774033 is a wasteful number, since it uses less digits than its factorization.
141133806774033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1699273.
The product of its (nonzero) digits is 3048192, while the sum is 51.
The spelling of 141133806774033 in words is "one hundred forty-one trillion, one hundred thirty-three billion, eight hundred six million, seven hundred seventy-four thousand, thirty-three".
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