Base | Representation |
---|---|
bin | 100000000110110000110011… |
… | …001111100110010001011010 |
3 | 200111221210120102012101222022 |
4 | 200012300303033212101122 |
5 | 122001424103331101414 |
6 | 1220151221450454442 |
7 | 41512344155252222 |
oct | 4006606317462132 |
9 | 614853512171868 |
10 | 141202204550234 |
11 | 40a9a578375583 |
12 | 13a05b24734422 |
13 | 60a3406960ba9 |
14 | 26c231a519082 |
15 | 114ced79e218e |
hex | 806c333e645a |
141202204550234 has 16 divisors (see below), whose sum is σ = 216866891386368. Its totient is φ = 68931891158592.
The previous prime is 141202204550201. The next prime is 141202204550243. The reversal of 141202204550234 is 432055402202141.
It is a super-2 number, since 2×1412022045502342 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 141202204550194 and 141202204550203.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4662585722 + ... + 4662616005.
It is an arithmetic number, because the mean of its divisors is an integer number (13554180711648).
Almost surely, 2141202204550234 is an apocalyptic number.
141202204550234 is a deficient number, since it is larger than the sum of its proper divisors (75664686836134).
141202204550234 is a wasteful number, since it uses less digits than its factorization.
141202204550234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9325201909.
The product of its (nonzero) digits is 76800, while the sum is 35.
Adding to 141202204550234 its reverse (432055402202141), we get a palindrome (573257606752375).
The spelling of 141202204550234 in words is "one hundred forty-one trillion, two hundred two billion, two hundred four million, five hundred fifty thousand, two hundred thirty-four".
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