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141426125634 = 23101772316107
BaseRepresentation
bin1000001110110110100…
…1110110101101000010
3111112001020012120100010
42003231221312231002
54304120042010014
6144545324405350
713134446142663
oct2035551665502
9445036176303
10141426125634
1154a843a7472
12234ab3a6856
131044b18a111
146bb8bc136a
153a2b027359
hex20eda76b42

141426125634 has 16 divisors (see below), whose sum is σ = 282880166688. Its totient is φ = 47137389312.

The previous prime is 141426125611. The next prime is 141426125653. The reversal of 141426125634 is 436521624141.

141426125634 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 141426125592 and 141426125601.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1096992 + ... + 1219115.

It is an arithmetic number, because the mean of its divisors is an integer number (17680010418).

Almost surely, 2141426125634 is an apocalyptic number.

141426125634 is an abundant number, since it is smaller than the sum of its proper divisors (141454041054).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141426125634 is a wasteful number, since it uses less digits than its factorization.

141426125634 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2326289.

The product of its digits is 138240, while the sum is 39.

Adding to 141426125634 its reverse (436521624141), we get a palindrome (577947749775).

The spelling of 141426125634 in words is "one hundred forty-one billion, four hundred twenty-six million, one hundred twenty-five thousand, six hundred thirty-four".

Divisors: 1 2 3 6 10177 20354 30531 61062 2316107 4632214 6948321 13896642 23571020939 47142041878 70713062817 141426125634