Base | Representation |
---|---|
bin | 1100110111010100000101… |
… | …0000011100101011101001 |
3 | 1212002012020002122122110000 |
4 | 3031311001100130223221 |
5 | 3323220234031332203 |
6 | 50025505142413213 |
7 | 2656620652303212 |
oct | 315650120345351 |
9 | 55065202578400 |
10 | 14144422136553 |
11 | 4563685608435 |
12 | 170534a431209 |
13 | 7b7a75a29997 |
14 | 36c8450d8409 |
15 | 197ddee7c4a3 |
hex | cdd4141cae9 |
14144422136553 has 20 divisors (see below), whose sum is σ = 21139465906768. Its totient is φ = 9425087705880.
The previous prime is 14144422136501. The next prime is 14144422136563. The reversal of 14144422136553 is 35563122444141.
14144422136553 is a `hidden beast` number, since 1 + 4 + 1 + 4 + 4 + 42 + 21 + 36 + 553 = 666.
It is not a de Polignac number, because 14144422136553 - 29 = 14144422136041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14144422136499 and 14144422136508.
It is not an unprimeable number, because it can be changed into a prime (14144422136563) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 41747383 + ... + 42084828.
Almost surely, 214144422136553 is an apocalyptic number.
It is an amenable number.
14144422136553 is a deficient number, since it is larger than the sum of its proper divisors (6995043770215).
14144422136553 is an equidigital number, since it uses as much as digits as its factorization.
14144422136553 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 83834306 (or 83834297 counting only the distinct ones).
The product of its digits is 1382400, while the sum is 45.
The spelling of 14144422136553 in words is "fourteen trillion, one hundred forty-four billion, four hundred twenty-two million, one hundred thirty-six thousand, five hundred fifty-three".
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