Base | Representation |
---|---|
bin | 10100100111000111011… |
… | …011100011010001110010 |
3 | 12000101221122220121022120 |
4 | 110213013123203101302 |
5 | 141201231333110004 |
6 | 3002403004015110 |
7 | 204221316306666 |
oct | 24470733432162 |
9 | 5011848817276 |
10 | 1416390128754 |
11 | 4a6762336647 |
12 | 1aa60a231496 |
13 | a3746456603 |
14 | 4c7a72d28a6 |
15 | 26c9c0193d9 |
hex | 149c76e3472 |
1416390128754 has 16 divisors (see below), whose sum is σ = 2833093692000. Its totient is φ = 472077803840.
The previous prime is 1416390128737. The next prime is 1416390128821. The reversal of 1416390128754 is 4578210936141.
It is a Smith number, since the sum of its digits (51) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a junction number, because it is equal to n+sod(n) for n = 1416390128697 and 1416390128706.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13001004 + ... + 13109495.
It is an arithmetic number, because the mean of its divisors is an integer number (177068355750).
It is a 1-persistent number, because it is pandigital, but 2⋅1416390128754 = 2832780257508 is not.
Almost surely, 21416390128754 is an apocalyptic number.
1416390128754 is an abundant number, since it is smaller than the sum of its proper divisors (1416703563246).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1416390128754 is a wasteful number, since it uses less digits than its factorization.
1416390128754 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26119545.
The product of its (nonzero) digits is 1451520, while the sum is 51.
The spelling of 1416390128754 in words is "one trillion, four hundred sixteen billion, three hundred ninety million, one hundred twenty-eight thousand, seven hundred fifty-four".
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