Search a number
-
+
1421004112113 = 32997168385367
BaseRepresentation
bin10100101011011010011…
…100100000000011110001
312000211212012221020121010
4110223122130200003301
5141240204023041423
63004444505421133
7204443543442345
oct24533234400361
95024765836533
101421004112113
114a870a859633
121ab49749a7a9
13a400032b591
144cac3dcd625
1526e6c120693
hex14ada7200f1

1421004112113 has 16 divisors (see below), whose sum is σ = 1980211927680. Its totient is φ = 905239727616.

The previous prime is 1421004112061. The next prime is 1421004112123. The reversal of 1421004112113 is 3112114001241.

It is not a de Polignac number, because 1421004112113 - 214 = 1421004095729 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1421004112113.

It is not an unprimeable number, because it can be changed into a prime (1421004112123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 84184245 + ... + 84201122.

It is an arithmetic number, because the mean of its divisors is an integer number (123763245480).

Almost surely, 21421004112113 is an apocalyptic number.

It is an amenable number.

1421004112113 is a deficient number, since it is larger than the sum of its proper divisors (559207815567).

1421004112113 is a wasteful number, since it uses less digits than its factorization.

1421004112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 168385496.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 1421004112113 its reverse (3112114001241), we get a palindrome (4533118113354).

The spelling of 1421004112113 in words is "one trillion, four hundred twenty-one billion, four million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 29 87 97 291 2813 8439 168385367 505156101 4883175643 14649526929 16333380599 49000141797 473668037371 1421004112113