Base | Representation |
---|---|
bin | 1100111011001100010011… |
… | …1001111010001100000011 |
3 | 1212022120012212202121001111 |
4 | 3032303010321322030003 |
5 | 3330313220131030201 |
6 | 50120245123144151 |
7 | 2664500125144366 |
oct | 316630471721403 |
9 | 55276185677044 |
10 | 14211055330051 |
11 | 4589969285998 |
12 | 1716245815057 |
13 | 7c11347a0c28 |
14 | 371b669040dd |
15 | 1999debe0b51 |
hex | cecc4e7a303 |
14211055330051 has 16 divisors (see below), whose sum is σ = 15508484288640. Its totient is φ = 12976486735680.
The previous prime is 14211055330001. The next prime is 14211055330103. The reversal of 14211055330051 is 15003355011241.
14211055330051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a de Polignac number, because none of the positive numbers 2k-14211055330051 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14211055329995 and 14211055330022.
It is not an unprimeable number, because it can be changed into a prime (14211055330001) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 109831065 + ... + 109960378.
It is an arithmetic number, because the mean of its divisors is an integer number (969280268040).
Almost surely, 214211055330051 is an apocalyptic number.
14211055330051 is a deficient number, since it is larger than the sum of its proper divisors (1297428958589).
14211055330051 is a wasteful number, since it uses less digits than its factorization.
14211055330051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 219791586.
The product of its (nonzero) digits is 9000, while the sum is 31.
The spelling of 14211055330051 in words is "fourteen trillion, two hundred eleven billion, fifty-five million, three hundred thirty thousand, fifty-one".
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