Base | Representation |
---|---|
bin | 1100111011010100000010… |
… | …1100101100101000011010 |
3 | 1212022202120121211121212022 |
4 | 3032311000230230220122 |
5 | 3330331443323211214 |
6 | 50121231154414442 |
7 | 2664602444456540 |
oct | 316650054545032 |
9 | 55282517747768 |
10 | 14213132241434 |
11 | 458a834684185 |
12 | 1716725291422 |
13 | 7c13a5b66889 |
14 | 371cc269dd90 |
15 | 199ab21e6d8e |
hex | ced40b2ca1a |
14213132241434 has 16 divisors (see below), whose sum is σ = 24414993539136. Its totient is φ = 6078936393600.
The previous prime is 14213132241383. The next prime is 14213132241443. The reversal of 14213132241434 is 43414223131241.
It is a super-2 number, since 2×142131322414342 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14213132241394 and 14213132241403.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1033825847 + ... + 1033839594.
It is an arithmetic number, because the mean of its divisors is an integer number (1525937096196).
Almost surely, 214213132241434 is an apocalyptic number.
14213132241434 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
14213132241434 is a deficient number, since it is larger than the sum of its proper divisors (10201861297702).
14213132241434 is a wasteful number, since it uses less digits than its factorization.
14213132241434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2067665941.
The product of its digits is 55296, while the sum is 35.
Adding to 14213132241434 its reverse (43414223131241), we get a palindrome (57627355372675).
The spelling of 14213132241434 in words is "fourteen trillion, two hundred thirteen billion, one hundred thirty-two million, two hundred forty-one thousand, four hundred thirty-four".
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