Base | Representation |
---|---|
bin | 1100111011101110001000… |
… | …0111101001001100101011 |
3 | 1212100102122200112011022220 |
4 | 3032323202013221030223 |
5 | 3330440314130414311 |
6 | 50124350124445123 |
7 | 2665241132411223 |
oct | 316734207511453 |
9 | 55312580464286 |
10 | 14220135404331 |
11 | 45927a879910a |
12 | 1717b5a6a97a3 |
13 | 7c1c50a0934c |
14 | 372388801083 |
15 | 199d71e38206 |
hex | ceee21e932b |
14220135404331 has 16 divisors (see below), whose sum is σ = 19574478701568. Its totient is φ = 9173024920800.
The previous prime is 14220135404297. The next prime is 14220135404333. The reversal of 14220135404331 is 13340453102241.
It is not a de Polignac number, because 14220135404331 - 217 = 14220135273259 is a prime.
It is a super-2 number, since 2×142201354043312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14220135404292 and 14220135404301.
It is not an unprimeable number, because it can be changed into a prime (14220135404333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9783340 + ... + 11142441.
It is an arithmetic number, because the mean of its divisors is an integer number (1223404918848).
Almost surely, 214220135404331 is an apocalyptic number.
14220135404331 is a deficient number, since it is larger than the sum of its proper divisors (5354343297237).
14220135404331 is a wasteful number, since it uses less digits than its factorization.
14220135404331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20933122.
The product of its (nonzero) digits is 34560, while the sum is 33.
Adding to 14220135404331 its reverse (13340453102241), we get a palindrome (27560588506572).
The spelling of 14220135404331 in words is "fourteen trillion, two hundred twenty billion, one hundred thirty-five million, four hundred four thousand, three hundred thirty-one".
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