Base | Representation |
---|---|
bin | 10100110000000111000… |
… | …010100011101101100011 |
3 | 12001022212200111100210210 |
4 | 110300013002203231203 |
5 | 141331021044101342 |
6 | 3011041141425203 |
7 | 205012531440123 |
oct | 24600702435543 |
9 | 5038780440723 |
10 | 1426047253347 |
11 | 4aa868552252 |
12 | 1b046440b203 |
13 | a46250b3712 |
14 | 4d041ac0c83 |
15 | 27164c4979c |
hex | 14c070a3b63 |
1426047253347 has 16 divisors (see below), whose sum is σ = 1924516379520. Its totient is φ = 939140668032.
The previous prime is 1426047253289. The next prime is 1426047253349. The reversal of 1426047253347 is 7433527406241.
It is not a de Polignac number, because 1426047253347 - 27 = 1426047253219 is a prime.
It is a super-3 number, since 3×14260472533473 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 1426047253296 and 1426047253305.
It is not an unprimeable number, because it can be changed into a prime (1426047253349) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1987179 + ... + 2607867.
It is an arithmetic number, because the mean of its divisors is an integer number (120282273720).
Almost surely, 21426047253347 is an apocalyptic number.
1426047253347 is a deficient number, since it is larger than the sum of its proper divisors (498469126173).
1426047253347 is an equidigital number, since it uses as much as digits as its factorization.
1426047253347 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 630002.
The product of its (nonzero) digits is 3386880, while the sum is 48.
The spelling of 1426047253347 in words is "one trillion, four hundred twenty-six billion, forty-seven million, two hundred fifty-three thousand, three hundred forty-seven".
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