Base | Representation |
---|---|
bin | 11010101100011000… |
… | …11100000011101010 |
3 | 1100222202022101111010 |
4 | 31112030130003222 |
5 | 213322214044424 |
6 | 10330015044350 |
7 | 1015064342121 |
oct | 152614340352 |
9 | 40882271433 |
10 | 14331003114 |
11 | 609452882a |
12 | 293b5106b6 |
13 | 14750733cc |
14 | 99d43aab8 |
15 | 58d218229 |
hex | 35631c0ea |
14331003114 has 16 divisors (see below), whose sum is σ = 28684787040. Its totient is φ = 4773204240.
The previous prime is 14331003107. The next prime is 14331003143. The reversal of 14331003114 is 41130013341.
It is a super-3 number, since 3×143310031143 (a number of 31 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 941017 + ... + 956124.
It is an arithmetic number, because the mean of its divisors is an integer number (1792799190).
Almost surely, 214331003114 is an apocalyptic number.
14331003114 is an abundant number, since it is smaller than the sum of its proper divisors (14353783926).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14331003114 is a wasteful number, since it uses less digits than its factorization.
14331003114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1898405.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 14331003114 its reverse (41130013341), we get a palindrome (55461016455).
The spelling of 14331003114 in words is "fourteen billion, three hundred thirty-one million, three thousand, one hundred fourteen".
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