Base | Representation |
---|---|
bin | 1000010110010110110… |
… | …0101000110110011001 |
3 | 111201020120220010221000 |
4 | 2011211230220312121 |
5 | 4322231132334431 |
6 | 145521231335213 |
7 | 13235402625204 |
oct | 2054554506631 |
9 | 451216803830 |
10 | 143440121241 |
11 | 5591823314a |
12 | 23971981509 |
13 | 106ac4c48b1 |
14 | 6d2a48093b |
15 | 3ae7c519e6 |
hex | 2165b28d99 |
143440121241 has 16 divisors (see below), whose sum is σ = 212626011520. Its totient is φ = 95571789840.
The previous prime is 143440121203. The next prime is 143440121257. The reversal of 143440121241 is 142121044341.
143440121241 is a `hidden beast` number, since 1 + 4 + 3 + 4 + 401 + 212 + 41 = 666.
It is not a de Polignac number, because 143440121241 - 210 = 143440120217 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (143440121261) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1478725 + ... + 1572738.
It is an arithmetic number, because the mean of its divisors is an integer number (13289125720).
Almost surely, 2143440121241 is an apocalyptic number.
It is an amenable number.
143440121241 is a deficient number, since it is larger than the sum of its proper divisors (69185890279).
143440121241 is a wasteful number, since it uses less digits than its factorization.
143440121241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3053213 (or 3053207 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 143440121241 its reverse (142121044341), we get a palindrome (285561165582).
The spelling of 143440121241 in words is "one hundred forty-three billion, four hundred forty million, one hundred twenty-one thousand, two hundred forty-one".
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