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143441112114 = 2332656316891
BaseRepresentation
bin1000010110010111000…
…0011010110000110010
3111201020122202111011000
42011211300122300302
54322231411041424
6145521304502430
713235414223066
oct2054560326062
9451218674130
10143441112114
115591884a653
122397217aa16
13106ac780901
146d2a65baa6
153ae7d9a3c9
hex2165c1ac32

143441112114 has 16 divisors (see below), whose sum is σ = 318758027040. Its totient is φ = 47813704020.

The previous prime is 143441112079. The next prime is 143441112173. The reversal of 143441112114 is 411211144341.

143441112114 is a `hidden beast` number, since 1 + 4 + 3 + 441 + 1 + 1 + 211 + 4 = 666.

It is a super-2 number, since 2×1434411121142 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1328158392 + ... + 1328158499.

It is an arithmetic number, because the mean of its divisors is an integer number (19922376690).

Almost surely, 2143441112114 is an apocalyptic number.

143441112114 is an abundant number, since it is smaller than the sum of its proper divisors (175316914926).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143441112114 is a wasteful number, since it uses less digits than its factorization.

143441112114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2656316902 (or 2656316896 counting only the distinct ones).

The product of its digits is 1536, while the sum is 27.

Adding to 143441112114 its reverse (411211144341), we get a palindrome (554652256455).

The spelling of 143441112114 in words is "one hundred forty-three billion, four hundred forty-one million, one hundred twelve thousand, one hundred fourteen".

Divisors: 1 2 3 6 9 18 27 54 2656316891 5312633782 7968950673 15937901346 23906852019 47813704038 71720556057 143441112114