Base | Representation |
---|---|
bin | 10100111101011001001… |
… | …110110110111010100011 |
3 | 12002200200202110102111020 |
4 | 110331121032312322203 |
5 | 142044224121030311 |
6 | 3021400401420523 |
7 | 206026152305661 |
oct | 24753116667243 |
9 | 5080622412436 |
10 | 1440311111331 |
11 | 505918089934 |
12 | 1b318533a743 |
13 | a5a89277881 |
14 | 4d9d623dc31 |
15 | 276ec0ecc06 |
hex | 14f593b6ea3 |
1440311111331 has 32 divisors (see below), whose sum is σ = 1944772001280. Its totient is φ = 948121824000.
The previous prime is 1440311111287. The next prime is 1440311111377. The reversal of 1440311111331 is 1331111130441.
It is not a de Polignac number, because 1440311111331 - 210 = 1440311110307 is a prime.
It is a super-2 number, since 2×14403111113312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1440311113331) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 53969311 + ... + 53995991.
It is an arithmetic number, because the mean of its divisors is an integer number (60774125040).
Almost surely, 21440311111331 is an apocalyptic number.
1440311111331 is a deficient number, since it is larger than the sum of its proper divisors (504460889949).
1440311111331 is a wasteful number, since it uses less digits than its factorization.
1440311111331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27547.
The product of its (nonzero) digits is 432, while the sum is 24.
Adding to 1440311111331 its reverse (1331111130441), we get a palindrome (2771422241772).
The spelling of 1440311111331 in words is "one trillion, four hundred forty billion, three hundred eleven million, one hundred eleven thousand, three hundred thirty-one".
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