Base | Representation |
---|---|
bin | 1000011000100100011… |
… | …0001001101111010001 |
3 | 111202202222101221001020 |
4 | 2012021012021233101 |
5 | 4324440201341423 |
6 | 150100204430053 |
7 | 13256203621365 |
oct | 2061106115721 |
9 | 452688357036 |
10 | 144034012113 |
11 | 560a2499152 |
12 | 23ab8848329 |
13 | 10775561904 |
14 | 6d852b72a5 |
15 | 3b2ee644e3 |
hex | 2189189bd1 |
144034012113 has 16 divisors (see below), whose sum is σ = 192957811200. Its totient is φ = 95566673664.
The previous prime is 144034012039. The next prime is 144034012123. The reversal of 144034012113 is 311210430441.
It is not a de Polignac number, because 144034012113 - 212 = 144034008017 is a prime.
It is not an unprimeable number, because it can be changed into a prime (144034012123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2682195 + ... + 2735367.
It is an arithmetic number, because the mean of its divisors is an integer number (12059863200).
Almost surely, 2144034012113 is an apocalyptic number.
It is an amenable number.
144034012113 is a deficient number, since it is larger than the sum of its proper divisors (48923799087).
144034012113 is a wasteful number, since it uses less digits than its factorization.
144034012113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57448.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 144034012113 its reverse (311210430441), we get a palindrome (455244442554).
The spelling of 144034012113 in words is "one hundred forty-four billion, thirty-four million, twelve thousand, one hundred thirteen".
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