Base | Representation |
---|---|
bin | 11010111000100011… |
… | …11111001101100010 |
3 | 1101020212110112001120 |
4 | 31130101333031202 |
5 | 214024334333442 |
6 | 10344103513110 |
7 | 1020444335220 |
oct | 153421771542 |
9 | 41225415046 |
10 | 14433121122 |
11 | 6137136582 |
12 | 2969758796 |
13 | 1490278c74 |
14 | 9acc1db10 |
15 | 59718a4ec |
hex | 35c47f362 |
14433121122 has 16 divisors (see below), whose sum is σ = 32989991232. Its totient is φ = 4123748880.
The previous prime is 14433121117. The next prime is 14433121133. The reversal of 14433121122 is 22112133441.
It is a junction number, because it is equal to n+sod(n) for n = 14433121092 and 14433121101.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 171822829 + ... + 171822912.
It is an arithmetic number, because the mean of its divisors is an integer number (2061874452).
Almost surely, 214433121122 is an apocalyptic number.
14433121122 is an abundant number, since it is smaller than the sum of its proper divisors (18556870110).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14433121122 is a wasteful number, since it uses less digits than its factorization.
14433121122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 343645753.
The product of its digits is 1152, while the sum is 24.
Adding to 14433121122 its reverse (22112133441), we get a palindrome (36545254563).
The spelling of 14433121122 in words is "fourteen billion, four hundred thirty-three million, one hundred twenty-one thousand, one hundred twenty-two".
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