Base | Representation |
---|---|
bin | 1101001101011011110011… |
… | …1000101101010101010011 |
3 | 1220102112011010112121110202 |
4 | 3103112330320231111103 |
5 | 3400432040033111011 |
6 | 50520235231445415 |
7 | 3026233331652020 |
oct | 323267470552523 |
9 | 56375133477422 |
10 | 14524453410131 |
11 | 469a871331045 |
12 | 1766b2a08686b |
13 | 81485b2bcc72 |
14 | 382db71d6547 |
15 | 1a2c3373623b |
hex | d35bce2d553 |
14524453410131 has 32 divisors (see below), whose sum is σ = 17268391620480. Its totient is φ = 11952614016000.
The previous prime is 14524453410013. The next prime is 14524453410133. The reversal of 14524453410131 is 13101435442541.
It is a de Polignac number, because none of the positive numbers 2k-14524453410131 is a prime.
It is a super-2 number, since 2×145244534101312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (14524453410133) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 639353585 + ... + 639376301.
It is an arithmetic number, because the mean of its divisors is an integer number (539637238140).
Almost surely, 214524453410131 is an apocalyptic number.
14524453410131 is a deficient number, since it is larger than the sum of its proper divisors (2743938210349).
14524453410131 is a wasteful number, since it uses less digits than its factorization.
14524453410131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40335.
The product of its (nonzero) digits is 115200, while the sum is 38.
Adding to 14524453410131 its reverse (13101435442541), we get a palindrome (27625888852672).
The spelling of 14524453410131 in words is "fourteen trillion, five hundred twenty-four billion, four hundred fifty-three million, four hundred ten thousand, one hundred thirty-one".
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