Base | Representation |
---|---|
bin | 100010000111011000111110… |
… | …111011111111110000101010 |
3 | 201200020211012011121100110120 |
4 | 202013120332323333300222 |
5 | 124131234334004333024 |
6 | 1251040030524424110 |
7 | 43414064561135223 |
oct | 4207307673776052 |
9 | 650224164540416 |
10 | 150041443433514 |
11 | 43898245278266 |
12 | 149b30539a8036 |
13 | 6594b02996539 |
14 | 290a08a5a424a |
15 | 1252dc79da479 |
hex | 88763eeffc2a |
150041443433514 has 16 divisors (see below), whose sum is σ = 300108363100320. Its totient is φ = 50009568438960.
The previous prime is 150041443433503. The next prime is 150041443433543. The reversal of 150041443433514 is 415334344140051.
It is a super-3 number, since 3×1500414434335143 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1061433157 + ... + 1061574504.
It is an arithmetic number, because the mean of its divisors is an integer number (18756772693770).
Almost surely, 2150041443433514 is an apocalyptic number.
150041443433514 is an abundant number, since it is smaller than the sum of its proper divisors (150066919666806).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
150041443433514 is a wasteful number, since it uses less digits than its factorization.
150041443433514 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2123019445.
The product of its (nonzero) digits is 691200, while the sum is 42.
Adding to 150041443433514 its reverse (415334344140051), we get a palindrome (565375787573565).
The spelling of 150041443433514 in words is "one hundred fifty trillion, forty-one billion, four hundred forty-three million, four hundred thirty-three thousand, five hundred fourteen".
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