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150142520000113 = 3797222831877399
BaseRepresentation
bin100010001000110111000111…
…100100011111111001110001
3201200121111002100222221110021
4202020313013210133321301
5124134413340110000423
61251154304350203441
743424303416600654
oct4210670744377161
9650544070887407
10150142520000113
11439270a3372823
1214a0a7621b3581
1365a14c0540824
142910d185c389b
1512558414cc95d
hex888dc791fe71

150142520000113 has 16 divisors (see below), whose sum is σ = 155797195478400. Its totient is φ = 144572021807616.

The previous prime is 150142520000029. The next prime is 150142520000153. The reversal of 150142520000113 is 311000025241051.

It is a cyclic number.

It is not a de Polignac number, because 150142520000113 - 213 = 150142519991921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (150142520000153) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 79034988 + ... + 80912386.

It is an arithmetic number, because the mean of its divisors is an integer number (9737324717400).

Almost surely, 2150142520000113 is an apocalyptic number.

It is an amenable number.

150142520000113 is a deficient number, since it is larger than the sum of its proper divisors (5654675478287).

150142520000113 is a wasteful number, since it uses less digits than its factorization.

150142520000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1899816.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 150142520000113 its reverse (311000025241051), we get a palindrome (461142545241164).

The spelling of 150142520000113 in words is "one hundred fifty trillion, one hundred forty-two billion, five hundred twenty million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 37 97 3589 22283 824471 1877399 2161451 69463763 79973687 182107703 6737985011 41834081917 1547861030929 4057905945949 150142520000113