Base | Representation |
---|---|
bin | 100010011010011110101011… |
… | …110000010001001100110001 |
3 | 201211220020011010011202212121 |
4 | 202122132223300101030301 |
5 | 124314232410412213131 |
6 | 1253522414343154241 |
7 | 43610624143626610 |
oct | 4232365360211461 |
9 | 654806133152777 |
10 | 151353234101041 |
11 | 44253600974485 |
12 | 14b8532ba45981 |
13 | 665b71975140b |
14 | 295376da39877 |
15 | 12770a1ad1911 |
hex | 89a7abc11331 |
151353234101041 has 16 divisors (see below), whose sum is σ = 173343617561088. Its totient is φ = 129455233992000.
The previous prime is 151353234101039. The next prime is 151353234101137. The reversal of 151353234101041 is 140101432353151.
It is not a de Polignac number, because 151353234101041 - 21 = 151353234101039 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 151353234100988 and 151353234101006.
It is not an unprimeable number, because it can be changed into a prime (151353234141041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3855130 + ... + 17820451.
It is an arithmetic number, because the mean of its divisors is an integer number (10833976097568).
Almost surely, 2151353234101041 is an apocalyptic number.
It is an amenable number.
151353234101041 is a deficient number, since it is larger than the sum of its proper divisors (21990383460047).
151353234101041 is a wasteful number, since it uses less digits than its factorization.
151353234101041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21677712.
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 151353234101041 its reverse (140101432353151), we get a palindrome (291454666454192).
The spelling of 151353234101041 in words is "one hundred fifty-one trillion, three hundred fifty-three billion, two hundred thirty-four million, one hundred one thousand, forty-one".
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